Hello, I'm new here and in the whole PHP world

I hit a wall trying to make a small script. I actually followed some tutorials and resulted in a problem. I want to pass on some Variable Values throu a Hidden Form type to another page and well I have the following prob

PHP Code:

 print  "<table align='center' border='1' cellpadding='0'><tr><td>
        <form method='post' action='final.php'>
        <input type='submit' name='keybutton' value='Show Key'></td></tr>";
print  "<input type='hidden' name='title' value='$title'>";
print  "<input type='hidden' name='makekey' value='$makekey'></form>"; 


I hoped that with these lines (lines are on the wordgame.php page) I could pass on the information of $title and $makekey to final.php through an Hidden Form type.

However , the line:

PHP Code:

 print  "<input type='hidden' name='makekey' value='$makekey'></form>" 


seems to print out my $makekey value (even printing out the " '> " afterwards) on the wordgame.php while I do not have the same problem with the $title which is one line above.

Don't know what I'm doing wrong.

PS. I haven't moved on to MySQL thats why I'm using this method. Sorry, I'm noob

Hey SNP,

As your code stands now you are printing out to the text document.
print 'ect...'; is all text.
print $makekey; is all variable.

So we have to compromise


print "<input type='hidden' name='makekey' value='".$makekey."'></form>"

Give that a go


P.S Were is makekey's value comming from?

Well it's a bit more complex than a simple value.

First of all:

PHP Code:

 $makekey=drawBoard($key); 


The drawBoard fuction code is:

PHP Code:

function drawBoard($board)
{
global $boardD,$title;

$puzzle="";
$puzzle.="<table align='center'  border='0' cellpadding='5' cellspacing='5'><caption><h3>$title</h3></caption>";
for ($i=0;$i<$boardD['height'];$i++){
    $puzzle.="<tr><font align='center'>";
    for ($j=0;$j<$boardD['width'];$j++){
        $puzzle.="<td><center>{$board[$i][$j]}</center></td>";
    }
    $puzzle.="</tr></font>";
    }
    return $puzzle;
} 


I also tried giving $makekey an easy value such as "lalala" and I didn't have the same problem. (It didn't print lalala on the wordgame.php page)

Will try and figure out if the error is somewhere else in the code. Until now I only though I had sth wrong with the escape code.

Thanx for replying


PS. I tried the approach you noted ACJavascript by using :

PHP Code:

 print  "<input type='hidden' name='makekey' value="'.$makekey.'"></form>"; 


Which returned a parse error. Tried it like this:

PHP Code:

 print  "<input type='hidden' name='makekey' value=".'$makekey'."></form>"; 


But had the same results as if I had used print ' ' , instead of " ". (variables didn't parse)

Syntacticly your code is correct, however try this just to humour me.

PHP Code:

print  "<input type=\"hidden\" name=\"makekey\" value=\"$makekey\"></form>"; 


It actually worked cptnwinky !!! Thanx!

Glad to be of service.