Trying to pass a PHP variable from one page (with a form) to another

**tirengarfio** · 01-16-2009, 07:53 AM

Hi,

i've written a form which sends what the user writes into the boxes to other web page.

In the same time, i would like to send to the receiving web page a PHP variable.

This is my try but it doesn't work. Any idea?

PHP Code:


			
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN" "http://www.w3.org/TR/html4/strict.dtd">
<html>
<head><title></title>

<style type="text/css" media=all>

</style>
</head>

<body>


<form method="POST" action="http://localhost/red_social/resultado_busqueda.php">

<?php

$var="Hola";

?>

<input type="text" name="nombre"><br>
<input type="text" name="apellidos"><br>
<input type="text" name="email"><br>
<input type="text" name="telefono"><br>
<input type="text" name="domicilio"><br>
<input type="text" name="fechanacimiento"><br>

<input type="submit" name="Buscar"><br>

<input name="flag" type="hidden" id="flag" value="<?php echo $_POST['flag'] ?>">



</form>


</body>

</html>

PHP Code:


			
<html>
<head><title></title>

<style type="text/css" media=all>

</style>
</head>

<body>

<?php

echo $_GET["flag"];

?>

</body>

</html>

**colbyt** · 08:29 AM

Quote:

is the reciever of the form information

On that page is where the php code should be placed. I usually have a debug routine to make sure it is getting there which I // remark out or remove when I am done. In your case my debug would look like.

PHP Code:


			
echo $_POST['whatever was submitted on the form']; //debug only
echo "br />; //debug only
echo $_post[the next item];//debug only

And I continue with the echos until I know I have all the submitted data getting to the right page and then I do whatever I want with it.

Once I get the sender and the reciever both working I incorporate them into one script or page but that topic is a little more advanced then you are ready for this morning.

**stoot98** · 01-16-2009, 08:33 AM

You are trying to print the variable from the $_GET array when you are POSTing the form and so it should be accessed from the $_POST array.

PHP Code:


			
<html>
<head><title></title>

<style type="text/css" media=all>

</style>
</head>

<body>

<?php

echo $_POST["flag"];

?>

</body>

</html>

**tirengarfio** · 01-16-2009, 08:53 AM

Quote:

Originally Posted by stoot98

You are trying to print the variable from the $_GET array when you are POSTing the form and so it should be accessed from the $_POST array.

PHP Code:


			
<html>
<head><title></title>

<style type="text/css" media=all>

</style>
</head>

<body>

<?php

echo $_POST["flag"];

?>

</body>

</html>

I tried that but it doesn't work...

**stoot98** · 01-16-2009, 10:07 AM

I would suggest checking the source of the form's page to make sure the hidden field is populated with a value from the $_POST['flag'] variable which from your code isnt likely to be set. You might want to use $_GET['flag'] if it is being passed from a link on the source page.

**mgraphic** · 01-19-2009, 08:28 PM

I think what you are trying to do is:

Page 1:

PHP Code:


			
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN" "http://www.w3.org/TR/html4/strict.dtd">
<html>
<head><title></title>
<style type="text/css" media=all>
</style>
</head>
<body>

<form method="POST" action="http://localhost/red_social/resultado_busqueda.php">
<?php
$var="Hola";
?>
<input type="text" name="nombre"><br>
<input type="text" name="apellidos"><br>
<input type="text" name="email"><br>
<input type="text" name="telefono"><br>
<input type="text" name="domicilio"><br>
<input type="text" name="fechanacimiento"><br>
<input type="submit" name="Buscar"><br>
<input name="flag" type="hidden" id="flag" value="<?php echo htmlentities($var) ?>">
 
</form>

</body>
</html>

Page 2:

PHP Code:


			
<html>
<head><title></title>
<style type="text/css" media=all>
</style>
</head>
<body>
<?php
echo htmlentities($_POST["flag"]);
?>
</body>
</html>