Hi
I have an oscommerce site, but I need some help.
I have a problem with customers clicking the confirm order button twice, which then duplicates there order.
I have put in big letters
PLEASE CLICK THIS BUTTON ONCE but that doesnt work, they still double click
I got some javascript that is supposed to stop the button being clicked twice, but it doesn't work.
Can anyone give me some code that does work, or something that changes the button message to ..... processing please wait, or something similer
I have put the code below, where the button is, but Im not a programmer so not sure what I would need to change.

PHP Code:

<?php if (isset($$payment->form_action_url)) {
    $form_action_url = $$payment->form_action_url;
  } else {
    $form_action_url = tep_href_link(FILENAME_CHECKOUT_PROCESS, '', 'SSL');
  }
  echo tep_draw_form('checkout_confirmation', $form_action_url, 'post');
the code that doesnt work is this
[php]<script language="JavaScript">
<!--
var _submitted = false;
validate = function () { 
_submitted = ( ! _submitted ) ? true : true ; 
if ( _submitted ) document.getElementById( "checkout_confirmation" ).submit() ;
}
-->
</script>
echo tep_image_submit('button_confirm_order.gif', IMAGE_BUTTON_CONFIRM_ORDER, ' onClick="validate();" ') . '</form>' . "\n";

if (is_array($payment_modules->modules)) {
echo $payment_modules->process_button();
}
echo tep_image_submit('button_confirm_order.gif', IMAGE_BUTTON_CONFIRM_ORDER) . '</form>' . "\n";
?>[/php]

I am absolutly desperate, so any help would be great

If you add the this.disabled=true; at the front of the onclick attribute and this.form.submit(); at the end, it will use js to disable the button once clicked as the form is submitting.

PHP Code:

echo tep_image_submit('button_confirm_order.gif', IMAGE_BUTTON_CONFIRM_ORDER, ' onclick="this.disabled=true;validate();this.form.submit();" ') . '</form>' . "\n"; 


Hi
inserted this line in the code

PHP Code:

echo tep_image_submit('button_confirm_order.gif', IMAGE_BUTTON_CONFIRM_ORDER, ' onclick="this.disabled=true;validate();this.form.submit();" ') . '</form>' . "\n"; 


that seems to prevent the button being clicked at all,
any advice

thanks

Try putting an onsubmit handler in your <form> tag.

<form onsubmit="document.getElementById('submit-button').disabled = true;">
...
<input type="submit" id="submit-button" ...

sorry ... not a programmer as i said


does this make this

<form onsubmit="document.getElementById('submit-button').disabled = true;">

echo tep_image_submit('button_confirm_order.gif', IMAGE_BUTTON_CONFIRM_ORDER) . '</form>' . "\n";

<input type="submit" id="submit-button"

because that gives me a parse error

this is the script it needs to go in

PHP Code:

if (is_array($payment_modules->modules)) {
    echo $payment_modules->process_button();
  }
    echo tep_image_submit('button_confirm_order.gif', IMAGE_BUTTON_CONFIRM_ORDER) . '</form>' . "\n";
?> 


sorry to be so dense

thanks

bump - please