Hi,

I am going to input a long string,which prompts a user for a time and date in the format

  hh:mm mm/dd/yyyy

It is valid only two digit for hour, month, date.
It is invalid to use one digit for hour such as 1:30 10/03/2005

    str= prompt("Enter the time and date in the format\n" + "hh:mm mm/dd/yyyy",
                                                                                              "00:00 01/01/2000");

how to write the regular expression.

Thank in advance!

zhshqzyc

This should work:

var str = prompt("Enter the time and date in the format\n" + "hh:mm mm/dd/yyyy","00:00 01/01/2000");

if (str.match(/^\d\d:\d\d[ ]\d\d\/\d\d\/\d{4}$/) != null) {
	alert("Format Correct");
} else {
	alert("Invalid Format");
}

thanks funkdaddu!

if the format is correct, how to output string?

I mean

document.writeln("please supply missing fragment");

The string is str:

document.writeln(str);

yes, however



str is str = prompt( "Enter the time and date in the format\n" +
"hh:mm mm/dd/yyyy",
"00:00 01/01/2000" );
how can I only to display the time and data part?

have a good day!

You can spilt the str string on the space into an array:

str.split(" ")[0]; //will give you the time
str.split(" ")[1]; //will give you the date

Hi, your answer is pretty great. But what is wrong with my expression?

reg = /^\d{2}:\d{2} \d{2}\/\\d{2}\/\\d{4}$/

I am a novice. I spent a lot time, still could not figure out,

the one more question is how to seperate the string into five part.

such as

RegExp.$1 = ...// hour
RegExp.$2 = ...// minute
RegExp.$3 = ...// month
RegExp.$4 = ...// day
RegExp.$5 = ...// year

It needs to remove the special characters such ":","/".

Thanks!

You just need to put each bit you want in between parentheses, and you don't need the double //:

reg = /^(\d{2}):(\d{2}) (\d{2})\/(\d{2})\/(\d{4})$/

then you can use the RegExp.$1 for the hour, RegExp.$2 for the minutes, RegExp.$3 for the Month... etc...

I appreciate your assistance.

God bless you!