take this code

PHP Code:

<select name="FileNo" id="select2" onChange="change_title();"> 
    <?  
$query="SELECT * FROM pationts"; 
$result=mysql_query($query) or die("error: " . mysql_error()); 
while($row=mysql_fetch_array($result)) 
{ 
    echo "bla"; 
?>   
<option value="<?php echo $row['FileNo'] ; ?>"><?php echo $row['FileNo'] ; ?></option>    
<? 
    }   
?> 
</select>

he above code is for list i need to select value from it and when i select value we must change vale on the below code
Code:

PHP Code:

<input name="PationtName" type="text" id="title"/> 


the result is :-
when i select FileNo:111 we print on PationtName: 111
this wrong we must print name of pationt who FileNo is 111

any help

I have read 5 times your previous post, but I cannot understand what is happening right now and what you want...

You are in the javascript forum, so no need to post your php code.
Show us the javascript code, and explain logically and step by step what you need, how and from where and what is the current behavior of your script.
That way we will be able to help

ok
i wont print name of pationt on here

PHP Code:

<input name="PationtName" type="text" id="title"/> 


but when i select his fileNo from here

PHP Code:

<select name="FileNo" id="select2" onChange="change_title();">  
    <?   
$query="SELECT * FROM pationts";  
$result=mysql_query($query) or die("error: " . mysql_error());  
while($row=mysql_fetch_array($result))  
{  
    echo "bla";  
?>    
<option value="<?php echo $row['FileNo'] ; ?>"><?php echo $row['FileNo'] ; ?></option>     
<?  
    }    
?>  
</select>

by using this java script

PHP Code:

function change_title(obj)
 { 
 document.getElementById('PationtName').value = obj.options[obj.selectedIndex].value;
} 


but the script not print name , it print FileNo >> why

because:

PHP Code:

value="<?php echo $row['FileNo'] ; ?>"

put the fileNo value in the value attribute of the option.
So, when you do

</span>
obj.options[obj.selectedIndex].value;

, it's what you get.

Put the pationt value on the value, and it should be ok.

PHP Code:

<option value="<?php echo $row['pationt'] ; ?>"><?php echo $row['FileNo'] ; ?></option>

ok show what i do
on Javascript part i write this code

PHP Code:

function change_title(obj)
 { 
document.getElementById('title').value  = document.getElementById('select2').options[selected_index].text;} 


and on body i write this code

PHP Code:

<select name="FileNo" id="select2" onChange="change_title();">   
    <?    
$query="SELECT * FROM pationts";   
$result=mysql_query($query) or die("error: " . mysql_error());   
while($row=mysql_fetch_array($result))   
{   
    echo "bla";   
?>     
<option value="<?php echo $row['Name'] ; ?>"><?php echo $row['FileNo'] ; ?></option>      
<?   
    }     
?>   
</select>

and

PHP Code:

<input name="PationtName" type="text" id="title"/> 


but not print name of pationt why ??!!!!

your javascript is false. It should be

document.getElementById('title').value  = document.getElementById('select2').options[document.getElementById('select2').selected_index].value;}

or, as I find it clearer to read:

var sel=document.getElementById('select2');
document.getElementById('title').value=sel.options[sel.selectedIndex].value;

and now, it should be ok.