I want to kno about permutation with string to find out possible combinations ! Suggest any link or part of code you know about this !

permutation or combination??

They are two different things.

Originally Posted by chrishirst

permutation or combination??

They are two different things.

Umm.. Permutation ! Want to use it in anagram program ! Thank you

See unicell's reply in http://www.daniweb.com/code/snippet216770.html

1. main()
2. {
3. int a[] = { 1, 2, 3, 4, 5, 6, 7, 8, 9 };
4. int count = 0;
5. do
6. {
7. if ( ( a[0] + a[1] + a[2] ) == 17 &&
8. ( a[0] + a[3] + a[6] ) == 17 &&
9. ( a[2] + a[5] + a[8] ) == 17 &&
10. ( a[2] + a[4] + a[6] ) == 17 &&
11. ( a[6] + a[7] + a[8] ) == 17 )
12. {
13. cout <<count << " : ";
14. for ( int i = 0 ; i <9 ; i++ )
15. cout <<a[ i ] <<" ";
16. cout <<"\n";
17. }
18. count++;
19. } while ( next_permutation( a, a + 9 ) );
20. cout <<count <<" permutations were tested\n";
21. return 0;
22. }

it would be better if you do google about the same .... its a vast topic may be you would like start with small example and then go forward ... start reading it will surely help better start with examples

sample code to write permutation in C,

#include<stdio.h>
#include<stdlib.h>
int lev=-1,n,val[50],a[50];
void main()
{
int i,j;
clrscr();
printf("Enter howmany numbers
");
scanf("%d",&n);
for(i=0;i<n;i++)
{
val[i]=0;
j=i+1;
scanf("%d",&a[j]);
}
visit(0);
getch();
}
visit(int k)
{
int i;
val[k]=++lev;
if(lev==n)
{
for(i=0;i<n;i++)
printf("%2d",a[val[i]]);
printf(" ");
}
for(i=0;i<n;i++)
if(val[i]==0)
visit(i);
lev--;
val[k]=0;
}